8t+4.9t^2-750=0

Solution for 8t+4.9t^2-750=0 equation:

8t+4.9t^2-750=0

a = 4.9; b = 8; c = -750;
Δ = b2-4ac
Δ = 82-4·4.9·(-750)
Δ = 14764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14764}=\sqrt{4*3691}=\sqrt{4}*\sqrt{3691}=2\sqrt{3691}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{3691}}{2*4.9}=\frac{-8-2\sqrt{3691}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{3691}}{2*4.9}=\frac{-8+2\sqrt{3691}}{9.8}
$